With a franchise deductible D and deductible amount d, the expected value of Y under a super policy is E[X] - E[min(X, D)] + d*S(d).

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Multiple Choice

With a franchise deductible D and deductible amount d, the expected value of Y under a super policy is E[X] - E[min(X, D)] + d*S(d).

Explanation:
The key idea is how the payout under this super policy breaks down and how to take expectations of those parts. The policy pays the amount by which a claim exceeds the franchise D, whenever X > D. That part is (X − D)+, where (·)+ means max with 0. It also pays an extra fixed amount d whenever the claim exceeds d, which contributes d times the probability that X > d (i.e., d·S(d)). So the total expected payout is E[(X − D)+] + d·P(X > d). Use the identity (X − D)+ = X − min(X, D) to get E[(X − D)+] = E[X] − E[min(X, D)]. Let S(d) denote P(X > d). Put these together: E[Y] = E[X] − E[min(X, D)] + d·S(d). This matches the given expression, since E[X] is the mean claim, subtracting E[min(X, D)] removes the part up to the franchise, and the term d·S(d) adds the extra fixed payment when the claim exceeds d.

The key idea is how the payout under this super policy breaks down and how to take expectations of those parts.

The policy pays the amount by which a claim exceeds the franchise D, whenever X > D. That part is (X − D)+, where (·)+ means max with 0. It also pays an extra fixed amount d whenever the claim exceeds d, which contributes d times the probability that X > d (i.e., d·S(d)).

So the total expected payout is E[(X − D)+] + d·P(X > d). Use the identity (X − D)+ = X − min(X, D) to get E[(X − D)+] = E[X] − E[min(X, D)]. Let S(d) denote P(X > d). Put these together:

E[Y] = E[X] − E[min(X, D)] + d·S(d).

This matches the given expression, since E[X] is the mean claim, subtracting E[min(X, D)] removes the part up to the franchise, and the term d·S(d) adds the extra fixed payment when the claim exceeds d.

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