If X is Uniform(a,b), what is Var(X)?

Study for the SOA Fundamentals of Actuarial Mathematics (FAM) Exam. Prepare with flashcards and multiple choice questions with detailed explanations. Get ready for your future as an actuary!

Multiple Choice

If X is Uniform(a,b), what is Var(X)?

Explanation:
Variance for a uniform distribution on an interval reflects how far, on average, values can be from the center, and it scales with the square of the interval length. For X ~ Uniform(a,b), you can think of X as a + (b−a)U where U ~ Uniform(0,1). Shifting by a does not change variance, and scaling by (b−a) scales the variance by (b−a)². Since Var(U) = 1/12 for a Uniform(0,1), we get Var(X) = (b−a)² × (1/12) = (b−a)²/12. A quick check using moments confirms this: E[X] = (a+b)/2 and E[X²] = (a² + ab + b²)/3, so Var(X) = E[X²] − E[X]² = (b−a)²/12. Thus the variance is (b−a)²/12.

Variance for a uniform distribution on an interval reflects how far, on average, values can be from the center, and it scales with the square of the interval length. For X ~ Uniform(a,b), you can think of X as a + (b−a)U where U ~ Uniform(0,1). Shifting by a does not change variance, and scaling by (b−a) scales the variance by (b−a)². Since Var(U) = 1/12 for a Uniform(0,1), we get Var(X) = (b−a)² × (1/12) = (b−a)²/12.

A quick check using moments confirms this: E[X] = (a+b)/2 and E[X²] = (a² + ab + b²)/3, so Var(X) = E[X²] − E[X]² = (b−a)²/12.

Thus the variance is (b−a)²/12.

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